# Управление качеством переходных процессов в многосвязных системах. Задание на курсовое проектирование, страница 7

XdId + Eq = U0cosd0                                                                            (2.22)

XqIq = U0sind0                                                                                    (2.23)

Tj                                                                                                                                                    — p2 d = Mт  – Me                                                                              (2.24)                wc

Trp [ Eq – (Xd–X'd)Id] + Eq = Er                                                           (2.25)

Линеаризованные уравнения переходных процессов электропередачи, работающей на мощную приемную систему запишутся в виде:

XdDId +DEq = Uшd0Dd                                                                          (2.26)

Tj               ¶P          ¶P                                                                                      —– p2Dd + — Dd + ––– DEq = 0                                                       (2.27)                   wc               ¶d          ¶Eq

Trp[ DEq – (Xd – X'd)DId] +DEq = DEr                                                  (2.28)

где Uшd0 = – U0sind0

Уравнение движения в полных единицах:

Tj                                                                                                                       — p2d=Mт – Me                                                                                 (2.29)                wc

в относительных единицах Ме = P

P = EQIq = Me                                                                                     (2.30)

Используя статорное уравнение  XqIq = U0 sind0, имеем:

U0                                                                                                                     Iq= ––– sind0                                                                                      (2.31)                 Xq

Необходимо привести уравнение (2.27) к базисным переменным. Тогда:

EqU0                                                                                                            P = ——– sind0                                                                                   (2.32)                      Xq

Поскольку линеаризовать необходимо по Eq, то:

EQ = Eq+Id(Xd – Xq)                                                                            (2.33)

EqU0               Id(Xd – Xq)U0                                                                       P = ——– sind0 + —————— sind0                                               (2.34)                  Xq                         Xq

Уравнение движения:

Tj                    Tj            EqU0              Id(Xd – Xq)U0                                            — p2 d + P = — p2d + –––— sind0 + —————— sind0                (2.35)                wc                    wc              Xq                         Xq