Графическое клиент-серверное приложение на примере интерполяции. Кусочно-линейная интерполяция, страница 2

double                          h, dataX[100], dataY[100];

} my_data_t;

my_data_t      msg_out, msg;

void   Inter( ){

int                         i=0, j=0;

double         Xh;

msg_out.maxX = msg.maxX;

msg_out.maxY = msg.maxY;

msg_out.h = msg.h;

Xh = msg.dataX[0];

msg_out.hdr.type = 0x00;

msg_out.hdr.subtype = 0x00;

while( i < msg.len ){

while( msg.dataX[i] <= Xh && Xh < msg.dataX[i+1] ){

msg_out.dataY[j] = (double)( msg.dataY[i]*(msg.dataX[i+1]-Xh) + msg.dataY[i+1]*(Xh-msg.dataX[i]) ) / (double)( msg.dataX[i+1]-msg.dataX[i] );

msg_out.dataX[j] = Xh;

j++;

printf("%d          %0.3f            %0.3f \n", j, msg_out.dataY[j-1], Xh );

Xh += msg.h;

if( j == 99 ) break;

}

i++;

if( j == 99 ) break;

}

msg_out.dataX[j] = Xh;

msg_out.dataY[j] = msg.dataY[i-1];

j++;

printf("%d          %0.3f            %0.3f \n", j, msg_out.dataY[j-1], Xh );

msg_out.len = j;

}

int main( int argc, char** argv ){

name_attach_t      *attach;

int                                      rcvid, i;

double                            data;

if( argc > 1 && !strcmp( argv[1], "global") ){

if ((attach = name_attach(NULL, ATTACH_POINT, NAME_FLAG_ATTACH_GLOBAL)) == NULL) {

printf("GLOBAL Name Attach Faild!!! \n");

return EXIT_FAILURE;

}

printf("GLOBAL channel \n");

}else{

if ((attach = name_attach(NULL, ATTACH_POINT, 0)) == NULL) {

printf("GLOBAL Name Attach Faild!!! \n");

return EXIT_FAILURE;

}

printf("LOCAL channel \n");

}

while (1) {

rcvid = MsgReceive(attach->chid, &msg, sizeof(msg), NULL);

if (rcvid == 0) {

/* Pulse received */

switch (msg.hdr.code) {

case _PULSE_CODE_DISCONNECT:

printf("Get pulse Disconnect\n");

ConnectDetach(msg.hdr.scoid);

break;

case _PULSE_CODE_UNBLOCK:

printf("Get pulse UNLBOCK\n");

break;

}

continue;

}

/* name_open() sends a connect message, must EOK this */

if (msg.hdr.type == _IO_CONNECT ) {

printf("Get Message IO_CONNECT\n");

MsgReply( rcvid, EOK, NULL, 0 );

continue;

}

printf("Server receive %d \n", msg.len);

printf("h = %f \n", msg.h);

for( i=0; i<msg.len; i++ )

printf( "X[%d] = %0.3f       Y[%d] = %0.3f \n", i, msg.dataX[i], i, msg.dataY[i] );

Inter();

MsgReply(rcvid, 0, &msg_out, sizeof( msg_out ) );

}

/* Remove the name from the space */

name_detach(attach, 0);

return EXIT_SUCCESS;

}

2. Тестирование

Формат входного файла:

N maxX maxY

x(0) y(0)

x(1) y(1)

…

x(N-1) y(N-1)

2.1. Тест1

test1.in

6 5 89

0 4

1 1

2 17

3 89

4 26

5 55

Клиент :

Рис.2.1. Результат выполнения теста 1

Сервер:

./inter LOCAL channel

Server receive 6

h = 0.500000

X[0] = 0.000       Y[0] = 4.000

X[1] = 1.000       Y[1] = 1.000

X[2] = 2.000       Y[2] = 17.000

X[3] = 3.000       Y[3] = 89.000

X[4] = 4.000       Y[4] = 26.000

X[5] = 5.000       Y[5] = 55.000

1          4.000            0.000

2          2.500            0.500

3          1.000            1.000

4          9.000            1.500

5          17.000            2.000

6          53.000            2.500

7          89.000            3.000

8          57.500            3.500

9          26.000            4.000

10          40.500            4.500

11          55.000            5.000

Get pulse Disconnect

2.2. Тест 2

Test2.in

10 9 50

0 50

1 40

2 30

3 20

4 10

5 0

6 10

7 20

8 30

9 40

Клиент:

Рис.2.2. Результат выполнения теста 2

Сервер:

./inter LOCAL channel

Server receive 10

h = 0.500000

X[0] = 0.000       Y[0] = 50.000

X[1] = 1.000       Y[1] = 40.000

X[2] = 2.000       Y[2] = 30.000

X[3] = 3.000       Y[3] = 20.000

X[4] = 4.000       Y[4] = 10.000

X[5] = 5.000       Y[5] = 0.000

X[6] = 6.000       Y[6] = 10.000

X[7] = 7.000       Y[7] = 20.000

X[8] = 8.000       Y[8] = 30.000

X[9] = 9.000       Y[9] = 40.000

1          50.000            0.000