Схема СЭУ в виде системы «входы-выходы». Алгоритм расчета систем уравнений по методу Зейделя (Расчетно-графические работы № 1-2), страница 5

                                                                               V = 3 × 3 – 2 × 1 = 7;

                                                                               Vz = 2 × 1 + 1 = 3;

                                                                               Vx = 7 – 4– 3 = 0.

XXI. Высокотемпературная секция воздухоохладителя

20

22

36

37

W0j

3

0

3

0

6


20

 

вода

 
                                                                                      J = 4;  N = 0;  L = 2;  W0 = 6.   

                                                                                      V = 3 × 4 – 2 × 0 = 12;

                                                                                      Vz = 2 × 2 + 1 = 5;

                                                                                      Vx = 12 – 6 – 5 = 1.

XXII. Низкотемпературная секция воздухоохладителя

23

37

W0j

3

0

6

 


                                                                                      J = 4;  N = 0;  L = 2;  W0 = 6.   

                                                                                      V = 3 × 4 – 2 × 0 = 12;

                                                                                      Vz = 2 × 2 + 1 = 5;

                                                                                      Vx = 12 – 6 – 5 = 1.

XXIII. Насос забортной воды

 


Номер связи

7

8

8

W0j

1

3

0

4

 


                                                                               J = 3;  N = 1;  L = 1;  W0 = 4.   

                                                                               V = 3 × 3 – 2 × 1 = 7;

                                                                               Vz = 2 × 1 + 1 = 3;

                                                                               Vx = 7 – 4– 3 = 0.

XXIV. Паровая турбина

Номер связи

2

3

5

W0j

3

0

1

4

                                       

XXIV

 
                                                     J = 3;  N = 1;  L = 1;  W0 = 4.   

                                              V = 3 × 3 – 2 × 1 = 7;

                                              Vz = 2 × 1 + 1 = 3;

                                               Vx = 7 – 4– 3 = 0.